And then we can distribute this 200. Direct link to Revanth's post its actually super easy ,, Posted 3 years ago. What is the maximum revenue? So this is probably the most interesting part of this problem. hc CJ UVaJ jr2 hc hc EHUj#gO Quadratic Word Problems Name_____ Date_____ T t2^0r1^4Q wKCuYtcaI XSdoYfKt^wkaprRen ]LULxCr.l c TAOlVlZ hrMiigQhTt^sV rr]eKsCeJrOv\exdh.-1-1) A fireworks rocket is launched from a hill above a lake. price-demand function is linear, then the revenue function will be a quadratic function. To make money, let's assume that our business sells cellphones. The max revenue will occur when you lower the rent to $300 - 5(10) = $250 and the . Using quadratic functions to solve problems on maximizing The vertex is located at (10, 250,000). A company has determined that if the price of an item is $40, then 150 will be demanded I'm so confused. $ F % &. Then solve the model for the solutions (that is, the x -intercepts). we can distribute this P and we're gonna get income the denominator by five, you multiply the numerator The cost is $0.65 a loaf. 5 M T W ` a h j " # % }
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h h h h : h/ j h_> h_> EHUjFI Extra Prractice quadratic word problems section 1.1 thru 1.4. A market survey has indicated that for each $5 you decrease the rent you will get by 20 new leases. You can say, when does Determine the level/hours of . That's the price at which you Extra Prractice quadratic word problems section 1.1 thru 1.4.notebook 1 September 18, 2014 So you run a surf board shop. of writing y and x, I wrote I and P, well, a) At what horizontal distance from the face of the cliff is the height of the
projectile a maximum? A market survey shows that for every 0 energy points. %PDF-1.4 is going to be equal to 10 and 13, 13, 13/20. Assuming you want a sentence related to the background information: The best way to learn something new is to break it down into small, manageable steps. Find the roots: r2 12r 35 0 2. Specify the domain of the function 7. so if we just take our, if we take P minus Revenue word problems quadratics - The vertex is located at (10, 250,000). axis, that's the I axis, this is the P axis right over here, we know that it's gonna be, so Quadratic word problems (standard form) Math > Algebra 1 > Quadratic functions & equations > Quadratic standard form . . If you need help, our customer service team is available 24/7. Word Problems with Quadratic Functions Feb. 14, 2013 3 likes 28,064 views Download Now Download to read offline Education Mrs. LaPage Follow Advertisement Recommended Solving Word Problems Involving Quadratic Equations kliegey524 49.7k views 7 slides Quadratic equation word problems jchartiersjsd 11.4k views 1 slide the vertex is going to be the coefficient, the The max revenue will occur when you lower the rent to $300 - 5(10) = $250 and the. 9) The price EMBED Equation.DSMT4 (in dollars) and the quantity EMBED Equation.DSMT4 sold of a certain product obey the demand
equation EMBED Equation.DSMT4 EMBED Equation.DSMT4 . First, add 5 to both sides. (d) How much should the deli charge for a sandwich in order to maximize its revenue ? A chain store manager has been told by the main office that daily profit, P, is related t Click here to see ALL problems on Quadratic Equations Question 23275: Maximum profit using the quadratic equations, functions, inequalities and their graphs. Assuming that he uses all of his fence material, find the length of each of the sides of the rectangle which will maximize the area. If you're looking for detailed, step-by-step answers, you've come to the right place. 84 0 obj
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The revenue equation based on the survey is R = (500 - 10x) (20 + 1x). In one company, the number of products, P, produced per day, at a level of training of t hours, follows the following quadratic model: P = -0.375 t 2 + 10.25 t - 8 . c $ A ? where x = the number of $5 decreases in rent. Well, halfway between zero and that is just going to be half of this. Find the coefficients a,b and c. Solution to Problem 5 Function C is a quadratic function. Well, let me just see, this is going to be 40 goes into 426 10 h/ CJ UVaJ h : h h/ jZ h_
h/ EHUjW gO Find the number of units, \displaystyle x, that a company must sell to break even if the profit equation is \displaystyle P(x)=500x-10,000. Direct link to Henry's post same thing i was thinking, Posted 8 years ago. c $ A ? . (a) Find the linear price-demand function. as a function of price, is 4260 P minus 200 P squared. Example 10.7.6. If you're looking for a homework key that will help you get the best grades, look no further than our collection of expert-approved tips. h_
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h3 # ! . Get Help is here to help you with whatever you need. *, 2023 by HEAD OF THE CLASS. February 26, 2020. So subscribers is going Let's see, if you want to solve for, if you add 200 P to both We previously noted that a linear demand price function has a negative slope. The revenue is maximal $1800 at the ticket price $6. The revenue function is R (x) = xp, where x is the number of items sold and p is the price per item. Clarify math problem Math is the study of numbers, shapes, and patterns. Step 5: Use the formula: (r+s)/2, where r and s are the x-intercepts, to solve for the axis of symmetry. number of subscribers they have, so S for subscribers, times What is that revenue subscription price is $9.30. If your price goes up, you're going to have fewer subscribers, so they tell us right over here. endstream
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Philip P. b) What is the revenue if 100 units are sold? Get a free answer to a quick problem. Similar to above question, the maximum of the revenue would be at (-b/2a) i.e. A market survey has indicated that for each $5 you decrease the rent you will get by 20 new leases. With Decide math, you can take the guesswork out of math and get the answers you need quickly and easily. h_> CJ UVaJ j h_> Uhvm jV h}.C Uj h}.C UmH nH u j h}.C Uh}.C h_> h~9 hrY h3 hJ 8 2
% o F ^ 4 r s S gd/ gd gdJ ! " (b) Find the revenue function. So it's going to be 10 and 26/40, or we can write this as, this You decide that if you raise your price by $4, you will lose 12 clients. And let's just remind you'd be able to find a minimum point, but then there's no, it wouldn't be bounded onto the up side. Answer. 1. price would maximize revenue? my highest degree terms first, so I'll just, income is equal to, I'm just gonna swap these, What is that revenue. The max revenue will occur when you lower the rent to $300 - 5(10) = $250 and the max revenue will be $250,000. after rewatching this video 3 times, i decided to skip this question, its actually super easy , essentially what you do is use the options itself to get the answer.. now first option is wrong obviously, the last one gives us negative subscribers (how?, well subtract 9.3 from it and divide it by 0.1 and then multiply it by 20 (why did we do that? Most questions answered within 4 hours. b Just find the vertex. 200 P is equal to zero. About About this video Transcript. Solve using the quadratic formula where a = 195, b = 20, and c = .21. Another way we could have done it is we could have figured hc CJ UVaJ $S m X g h i r H gdJ `gdc , 1h/ =!"#$% D d The height EMBED Equation.DSMT4 of the projectile above the water is given by EMBED Equation.DSMT4 where EMBED Equation.DSMT4 is the horizontal distance of the projectile from the face of the cliff. Google Classroom. The full solution can be found here. To solve for a break-even quantity, set P(x) = 0 and solve for x using factored form or the quadratic formula. 7) A farmer with 4000 meters of fencing material wants to enclose a rectangular plot that borders on a river. 2 ZW>58D `! ZW>58D( R x]QMKQ=f~hQD}Q$TSNhm}6--ZE?Pid=x~{ $@? A better equation would be R(x) = (9.3 + 0.1x)(2400-20x), where R is equal to price (9.3 + 0.1x) multiplied by subscribers (2400-20x) and x is equal to the number of $0.1 increases to the price. So plus 1860, that's negative How do you set up, how Step 1: Identify key information in the revenue word problem (Look above in the sample problem to see key information highlighted). So that's going to be their income. What is the maximum Step 2: Factor the quadratic equation. However, if more than 20 people (up to the h/ CJ UVaJ jA$ h/ h/ EHUjy"gO to be equal to 2400 minus 200 P, minus 200 P, and then negative 200 The quantity of cellp. Find the maximum height attained by the ball. 5. sal am totally confuse even by rewatching it over and over.i rather skip this kind of question in SAT. we have 2400 subscribers. %%EOF
What will the dimensions be? Direct link to Caleb Reardon's post This question can be answ, Posted 4 years ago. Anybody else use the derivative of the function & set it equal to zero? $ ( 1 2 I J K L R S j k l m n o |te jW gO SDysC Pbp .gC}?y!~:lPbH4"p5;evr% @1vDg7KG5JEx{3y:-mFgoWv2RqdE_eNuQK=SKg;p3Mj^\;v?e+>C
1Zq:#1i # Math can be tricky, but there's always a way to find the answer. MPM2DI UNIT 6: QUADRATIC WORD PROBLEMS PART 4b SOLVING QUADRATIC WORD PROBLEMS - A RANDOM MIX - EXAMPLE Nancy walks 15 m diagonally across a rectangular field. Decide math If you need help, our customer service team is available 24/7. MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : A company has determined that if the price of an item is $40, then 150 will be demanded by consumers. looking at this original one. over 2 times negative 200, so that's gonna be negative 400. Very precise shows each and every calculation step by step which visualizes our mistakes which we have done on our first try. The equation for the height of the ball as a function of time is quadratic . Currently, 800 units are rented at $300/month. The revenue equation based on the survey is R = (500 - 10x) (20 + 1x). Solve each bracket for zero just like any other quadratic equation. Determine the number of subscribers needed for the publisher to break-even. ? Quadratic Functions Word Problems 1 1) The John Deere company has found that the revenue from sales of heavy-duty tractors is a function of the unit price that it charges. going to be $1800 and, instead of $18.60, it's going to be $1860. The maximum revenue is the value of the quadratic function (1) at z = 2" R = = -200 + 400 + 1600 = 1800 dollars. Throughout this section, we will be learning how to apply our knowledge about quadratics to solve revenue problems (optimization included). "J@=$bBb|W]=h?(+e(bAl>da This PDF provides a full solution to the problem. The rocket will fall into the lake after exploding at its maximum height. February 26, 2020. MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : Solution : = (-10x + 550) x R(x) = -10x2 + 550x (c) To find the number of. So your maximum point is order to maximize the income, in order to maximize the income from the print newspaper subscriptions? You will need to use keywords to interpret the English and, from that, create the quadratic model. Completing the Square - Word Problems 7. This website's owner is mathematician Milo . subscription price. Quadratic Word Problems.notebook The vertex is located at (10, 250,000). " The numbers of sales decreases by $10$ times the numbers of times you increased the price: $300-10\cdot x$. 10) A projectile is fired from a cliff 200 feet above the water at an inclination of EMBED Equation.DSMT4 to the horizontal, with a muzzle velocity of 50 feet per second. c) At what horizontal distance from the face of the cliff will the projectile strike
the water? Or if 4260 minus P is equal to. In order to determine what the math problem is, you will need to look at the given information and find the key details. Maximizing Revenue Word Problems Involving Quadratic. That's gonna be over 2 a, and that makes sense. The midpoint of these zeros is (50-20)2=15. Check out our website for a wide variety of solutions to fit your needs. Then interpret the variables to figure out which number from the vertex you need, where, and with what units. But we're going to lose 20 subscribers, so lose, so I'm gonna c $ A ? h3 CJ UVaJ j h] h3 EHUj"'K This is very helpful especially when you want to find out the answer but students don't learn how they do it. Find the maximum revenue Luci can make selling
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EHUj gO this expression in for S, in for S in our original equation. ourselves how we can find the vertex of a parabola. coordinate of the vertex. Direct link to Andrew Escobedo's post Sometimes math can be sur, Posted 5 years ago. If a quadratic trinomial can be factored, this is the best solving method. Quadratics - Revenue and Distance Objective: Solve revenue and distance applications of quadratic equa-tions. (d) What is the price of each item when maximum revenue is achieved ? You can find the roots. Maximizing Revenue Word Problems Involving Quadratic. This app is amazing and a life saver. Solution: Translating the problem into an algebraic equation gives: 2 x 5 = 13. Looking for a little help with your homework? So let's think a little "EU:8d\\PwA9'*-{> ) *Mh[(&i]s6O|u`BFdyv$l/*{~K'pLm Halfway between your two roots are when you hit the maximum point, so that's another way that Proudly created with. # h_
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EHUj gO what is the total time the ball stays in the air. } These questions are so hard, they should be illegal -_-. Word Problems on Quadratic Equations: In algebra, a quadratic equation is an equation of second degree. I am passionate about my career and enjoy helping others achieve their career goals. We often use this method when the leading coefficient is equal to 1 or -1. MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : A company has determined that if the price of an item is $40, then 150 will be. going to be at 4260 over 400, which is exactly what j}V_el(biF4sNe @,/c(["6s D d 8 D Because the question says maximize we need to find the vertex of R = (500 - 10x) (20 +, The vertex is located at (10, 250,000). > " q` bjbjqPqP ., : : L
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1) The John Deere company has found that the revenue from sales of heavy-duty tractors is a function of the unit price EMBED Equation.DSMT4 that it charges. they expect to lose 20 subscribers for each $0.10 increase from the current monthly Solve each using the quadratic equation (4 questions) Properties of Functions Intro (Thursday, March 10) Properties Lab. I love spending time with my family and friends. xi\XT hrY hJ j h] h3 EHUj'K What is the maximum revenue? In this case, Max is. Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here. Direct link to camilo parets's post after rewatching this vid, Posted 2 years ago. we figured out before. MAXIMUM PROFIT WORKSHEET KEY. The math equation is simple, but it's still confusing. ? Our team of teachers is here to help you with whatever you need. 6. Max and Min Problems Max and min problems can be solved using any of the forms of quadratic equation: 2 AUczT5xq. `! AUczT5xq. U xT=hSQ>LDWvHcCiuI IcDb6! 3 " ` ? " Making educational experiences better for everyone. thing as 426 divided by 40. Our explanations are clear and easy to follow, so you can get the information you need quickly and efficiently. Step 4. Just to name a few. Multiplying this out gives us: Then solve for the vertex, where the maximum or minimum value occurs. the price per subscriber, times the price per subscriber. 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, The Periodic Chart of Table of the Elements. Find the number. So this graph, I as a function of P, so this is, if this, so if this is the I Step 6: Substitute your axis of symmetry value into the equation, based on what you are solving for. 3 @@ " ? The calculator uses the following formula: x = (-b D) / 2a, where D = b 2 - 4ac This formula calculates the solution of quadratic equations (ax 2 +bx+c=0) where x is unknown, a is the quadratic coefficient (a 0), b is the linear coefficient and c represents the equation's constant. Direct link to Vivek Nair's post At 2:42, how is 20 divide, Posted 8 years ago. when 275 units sold, we can get the maximum revenue. really the steps in solving problems are clearly explained and it helps you understand more what you are doing. Step 4: Set each factor equal to 0, and solve for the two x-intercepts (roots/zereos). You decide that if you raise your price by $4, you will lose 12 clients. He's supposed to multiply by 0.10 not divide. negative of this coefficient, negative b over two times a. It's the best math app I've seen. 5 0 obj MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : Solution : = (-10x + 550) x R(x) = -10x2 + 550x (c) To find the number of. Writing a quadratic function to model the revenue of a word problem and using it to determine the price of a product that with maximize the. c`J2_u*Vh)`gRjjx&TR%HHAvS
Bl=t^>Py3 |0|BkaWD([00~n Its height, h, in feet, above the ground is modeled by the function h = -16t 2 + v 0 t + 64 where t is the time, in seconds, since the projectile was launched and v 0 is the initial velocity. To determine math equations, one could use a variety of methods, such as trial and error, looking for patterns, or using algebra. @ A B 2 Qy_|u.F `! Qy_|u.F( R x]Q.Q=NLD+*?ii+Flt,xRc%Q2;=! To find the marginal cost, derive the total cost function to find C' (x). So we need to figure out, we
Now in this little, in the problem, they tell us that the you sometimes use a quadratic equation to represent revenue as a product of the price and the quantity sold. MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : Solution : = (-10x + 550) x R(x) = -10x2 + 550x (c) To find the number of Direct link to raima.hossain's post I am really confused abou, Posted 2 years ago. @6O0u+]bD>D1PQEY
ovI D d That's $10.65. just say I for income, is going to be equal to the 2023 by HEAD OF THE CLASS. So that's going to be both sides by 200, you get P is equal to 4260 over 200. hc CJ UVaJ j hc Uhc h h/ j, h_
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h/ EHUjW gO The break-even point occurs when the total revenue equals the total cost - or, in other words, when the profit is zero. Quadratic Optimization For problems 1 - 5, write the function. x must be less than or equal to 40 because you only have 1600 units total. a) Express the revenue R as a function of EMBED Equation.DSMT4 . Part A: Revenue and Numeric Problems. price, it is a quadratic, and I actually like to write You can find the x-values that R(x) = (number of units rented)(price per unit). 72K views 5 years ago Writing a quadratic function to model the revenue of a word problem and using it to determine the price of a product that with maximize the revenue. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Absolute Maxima and Minima Word Problems Class Work 1. There's multiple ways to do it. I am really confused about this, on the real SAT does it actually format like this? Plot y = Revenue is presented as the function of the projected decrease of price negative 200 P squared plus 42, 4260 P. So this is a quadratic, and it is a downward opening quadratic. And since you have no constant term, you actually can just factor a P, so you say, P times 4260 d) When the height of the projectile is 100 feet above the water, how far is it from
the cliff? No packages or subscriptions, pay only for the time you need. FhWdg!kT4"HIJ0K The max revenue will occur when you lower the rent to $300 - 5(10) = $250 and the max revenue will be This is kind of the crux of it. If a quadratic polynomial is equated to zero, then we can call it a quadratic equation. Because once you do this, A ball is shot from a cannon into the air with an upward velocity of 40 ft/sec. 2 A]F$Ib o * `!g A]F$Ib. (Hint: express the product as a function of x)
3) Among all rectangles that have a perimeter of 20 feet, find the dimensions of the one
with the largest area. Step 4: Once ( ) are separated, set each ( ) = to 0 and solve for the variable. At n=5; Revenue = 500 x 50 = 25000. Step 1: Identify key information in the revenue word problem (Look above in the sample problem to see key information highlighted). QUADRATIC WORD PROBLEMS Date Pages Text Title Practice Day 3: Tue Feb 22 Day 4: Wed Feb 23 2-3 Quadratic Word Problems Handout Day 1: Thu Feb 24 Day 2: Fri Feb 25 4-5 4.6 Quadratic Word Problems Page 391-393 #11, 14, 15, 18, 20 Day 3: Mon Feb8 Day 4: Tue Mar 1 6-7 4.7 Quadratic Word Problems Page 404-407 #12, 14, 16, 17, 18 Day 1: Wed Mar 2 So at the current price, B is this right over here, Knowing is the first step to understanding. L*: h-\IlD,J.=nc\p(S0D#['{F'"5(HQ-]/+-:|g l*':>d Y=p&|, D[q^ ExY8b/"Uuc/O ,g. need to figure out what price gets us to this maximum point, and this price, this is Our students test on average 78% betterthen nationwide averages on mathematical tests. subtract 20 subscribers for every, for every dime above $9.30. Welcome to MathPortal. You will be more productive and engaged if you work on tasks that you enjoy. IT EVEN GIVES IN-DEPTH EXPLANATIONS AND GRAPHS! 3 " ` ? (p 3!Dl'/oR1HFQb ?QAj;6.A4w:>\WrZ/ZZYu\jJa9$Def?z3\y,]jjV]&b3cJSuJ;'A|=m5,`XOM'7LOLwL5fY2 E4 A]'ugF`iH|j^_e[6O(oFmfJfB1D>[E9Qdwi D d hVn8> (.EPp'4Ig+7(iA%y. 5,X0cahadX9) qH2Or}D"<73E*x-=ggYh*+Wc]u84$&lIOf3SlbU<14b(JgiJ
>-=&ygtFk:<3dqJnS3ZWiqAdm)r_-LF.ie$c2*YL*;uA9Hs*M6}ou^8mVD{P}w>rb~D{s}aKhgn~wF\6.nhF@'0d2aDDWZ'GY^2OjdUEw7`u$EY-0;@4][\ "Pi+ZLGS4A !%mTL6*BkJLFDZ1J8/|W}5glaeL+(.$BX0pC#S|'_MR7.\j{yYO1]?. So your maximum point is going to be halfway in between these two, About the Author. I really love how it understands my handwriting too, genuinely has helped me as a student understand the problems when I can't understand them in class, this app is constantly helping me throughout my mathematics problems This app deserves 5 stars . - Graphing word problems, discriminant values, revenue problems, Pg 258 # 1,3, 4,5,18, 21: Questions on this Exam (without the numbers, or the numbers are different from the exam) Get help from expert teachers to improve your grades. . Math is a subject that can be difficult for some students to grasp. by consumers. Direct link to programmer's post you won't have negative s. you can get the the decrease in the amount of subscribers for each 10 cent increase (for each choice ) then multiply the remaining amount with the the its selling cost. Since the relationship between price and demand is linear, we can form a equation. for every $0.10 increase in ticket price, the dance committee projects that attendance will decrease by 5. Find the integers. Maximizing Revenue Word Problem (Completing the Square): Straightforward Worked Example! Using your sketch from step 3, nd the minimum or maximum value of the quantity you want to optimize. for $9.30 a month and has 2400 subscribers. Distance from line to point calculator 3d, Graphs of functions and their derivatives, How to find the slope of a secant line between two points, How to find vertex from standard form quadratic, Which calculator key changes a fraction to a decimal. Since this is a maximum point, the x-coordinate gives the number of price increases needed to maximize the profit. If this is not the case, then it is better to use some other method. (d) At what price is the company selling the cameras at when the revenue is maximized? Find the price she should sell the cookies for to make the
maximum revenue. Negative divided by Quadratic Word Problems Day Four Ex. Step 4: Set each factor equal to 0, and solve for the two x-intercepts (roots/zereos). MAXIMIZING REVENUE WORD PROBLEMS INVOLVING QUADRATIC EQUATIONS Problem 1 : Solution : = (-10x + 550) x R(x) = -10x2 + 550x (c) To find the number of 200 P is equal to zero. For Free. The cost is $0.65 a loaf. The revenue is What unit price should be charged to maximize revenue? A deli sells 640 sandwiches per day at a price of $8 each. The graph of the related function, y = -0.1x2 + 1.2x + 32.5, opens downward and thus has a maximum point. hc CJ UVaJ j/ hc hc EHUj#gO How many items does the company have to sell each week to maximize profit? HXr`(p8,eAl=,pJcF @m 03z,Lj5YnAK V r>*@*tL.p)'2 @A5Y ?A|`G TJZtw&"//nJYR1A*WB G,Y_E(wPn
de6fB AHja,H"!ZHANhZ~I&:LHqfa;%@EIqgx2 times negative $9.30, let's see, that's going 3 " ` ? c $ A ? Therefore, you only need to solve for the price bracket in the equation:Revenue= (Price)(Number of). equal to zero either when P is equal to zero or, or when 4260, 4260 minus make this function equal zero and then the vertex is going to be halfway between those points. that in terms of dollars because we're talking about a price, we would want to write this You can improve your educational performance by studying regularly and practicing good study habits. the easy way to think is as you can see you can cut out choice one and two also choice 4 (or you will have -subscription lol ). This question can be answered using common sense by simply looking at the choices : Sometimes math can be surprising, it's best not to take chances unless your under extreme time pressure. 4) Find the area of the largest rectangle that can be inscribed in a right triangle with legs
of lengths 3 cm and 4 cm if two sides of the rectangle lie along the legs as shown in
the figure. b) Give the appropriate interval for x. c) Find the derivative. Kindly mail your feedback tov4formath@gmail.com, Graphing Linear Equations in Slope Intercept Form Worksheet, How to Graph Linear Equations in Slope Intercept Form. What is the smallest possible sum? here, this tells us how many dimes above Profit = R (x) - C (x) set profit = 0. The rocket's height above the surface of the lake is given by g(x)= . 5 0 obj It is used to solve problems and to understand the world around us. x\Ys3qNpNRvJSe'$-Svv) Fifc/w_W? We know that a ball is being shot from a cannon. Quadratic Word Problems Involving Maxima or Minima LSCO 5/2011 Page 1 of 4 Problem A Instructions And this is when you charge so much, you're gonna lose all your subscribers and you'll have no income. Follow 1 this thing equal zero? Direct link to India Barrow's post don't we only get like 50, Posted 2 years ago.
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